If bond enthalpies of $N \equiv N$,$H - H$ and $N - H$ bonds are $x_1, x_2$ and $x_3$ respectively,$\Delta H_f^o$ for $NH_3$ will be

  • A
    $x_1 + 3x_2 - 6x_3$
  • B
    $\frac{1}{2}x_1 + \frac{3}{2}x_2 - 3x_3$
  • C
    $3x_3 - \frac{1}{2}x_1 - \frac{3}{2}x_2$
  • D
    $6x_3 - x_1 - 3x_2$

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Similar Questions

From the following bond energies:
$H-H$ bond energy$431.37 \text{ kJ mol}^{-1}$
$C=C$ bond energy$606.10 \text{ kJ mol}^{-1}$
$C-C$ bond energy$336.49 \text{ kJ mol}^{-1}$
$C-H$ bond energy$410.50 \text{ kJ mol}^{-1}$

Enthalpy for the reaction $CH_2=CH_2 + H-H \to CH_3-CH_3$ will be .............. $\text{kJ mol}^{-1}$

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The enthalpy of combustion of propane,graphite and dihydrogen at $298 \ K$ are: $-2220.0 \ kJ \ mol^{-1}$,$-393.5 \ kJ \ mol^{-1}$ and $-285.8 \ kJ \ mol^{-1}$ respectively. The magnitude of the enthalpy of formation of propane $(C_{3}H_{8})$ is ......... $kJ \ mol^{-1}$. (Nearest integer)

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